Question

If the student hears a sound at 35 dB, what is the intensity of the sound?

Answer 1

The intensity of the sound is
`3.16* 10^(-9)\ W/m^2`.

Step-by-step explanation:

It is given that,

Sound heard by the student, i = 35 dB

To find,

The intensity of the sound

Solution,

The intensity of sound is given by the following formula :

`i=10\ log((I)/(I_o))`

Where

`I_o=10^(-12)\ W/m^2` is the minimum intensity of human being

I is the intensity of the sound

`35=10\ log((I)/(10^(-12)))`

`I=3162.27* 10^(-12)\ W/m^2`

`I=3.16* 10^(-9)\ W/m^2`

So, the intensity of the sound is
`3.16* 10^(-9)\ W/m^2`.

Answer 2

To solve for the intensity level of the sound heard by the student at 35 dB, we have the solutions enumerated below:
1. Divide the decibels by 10
35/10=3.5
2.Use the value as exponent
10^3.5=3162.28
3. Find the intensity
I/10^-12W/m²=10^3.5
I=3.1624^-9 W/m²