Question

Four wires running through the corners of a square with sides of length 8.11 cm carry equal currents, 3.19 A. Calculate the magnetic field at the center of the square.

Answer 1

We will have the following:

First, we determine the distance:

`r=(8.11√(2))/(2)cm\Rightarrow r=4.055√(2)cm`

Then, we will have that:

`\begin{gathered} B=((4\pi\ast10^(-7)Tm/A)(3.19A))/(2\pi(4.055√(2)cm\ast(1m)/(100cm)))\Rightarrow B=1.126427282...\ast10^(-5)T \\ \\ \Rightarrow B\approx1.13\ast10^(-5)T \end{gathered}`

So, the magnetic field is approximately 1.13*10^-5 T.