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Sin(x+22)°=cos(2x−7)°

2 Answers

4 votes

Answer:

x = 25

Explanation:

Given :
\sin (x+22)^(\circ)=\cos (2x-7)^(\circ)

We have to find the value of x.

Consider the given
\sin (x+22)^(\circ)=\cos (2x-7)^(\circ)

We know,


\sin\theta=\cos(90^(\circ)-\theta)

Consider the left side
\sin (x+22)^(\circ)=\cos(90^(\circ)-(x+22)^(\circ))

thus,


\sin (x+22)^(\circ)=\cos (2x-7)^(\circ) becomes,


\cos(90^(\circ)-(x+22)^(\circ))=\cos (2x-7)^(\circ)

Simplify for x,


\cos(68-x)=\cos (2x-7)

Thus, 68 - x = 2x - 7

Adding x both side , we have

68 = 3x - 7

Adding 7 both side, we have,

75 = 3x

Divide both side by 3, we have,

x = 25

Thus, x = 25

User Bijay Singh
by
7.5k points
4 votes
To answer this, it must be noted that the trigonometric functions sine and cosine will have the same values if the angles are complementary (meaning, their sum is 90°).
90 = (x + 22) + (2x - 7)
The value of x from the equation is 25.
User Smills
by
8.2k points

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