Question

In a trapezoid ABCD with legs AB and CD , the diagonals intersect each other at point O. Compare the areas of △ABD and △ACD

Answer 1

Answer with explanation:

In Trapezoid A B CD, having legs AB and CD. it is also given that Diagonals AC and B D intersect each other at O.

In a trapezium one pair of Opposite sides are parallel.

That is , AD ║ BC.

→→Area(ΔABD)=Area(ΔACD)

→Triangles on the same base and between the same parallel are equal in area.

→AD, is the same base of two triangles ,△A B D and △A CD and AD ║ BC.

Answer 2

The area of △ABD and △ACD are equal.

Explanation:

Triangles lying on same base and between same parallels are equal in area .

In a trapezoid the opposite sides are parallel.The legs of the trapezoid are AB and CD.The triangles △ABD and △ACD are having the same base AD and are lying between the same parallel lines AB and CD,so they are w=equal in area.