Question

Mg2+,Cr4+,I-,O2- formulas

Answer 1

`MgI_2\\\\MgO\\\\CrI_4\\\\ CrO_2`

Step-by-step explanation:

Hello!

In this case, we can notice that among the given ions, Mg2+ and Cr4+ are cations and I- and O2- are anions, thus, for each resulting compound we switch the oxidation states as subscripts to get:

`Mg^(2+)I^- \rightarrow MgI_2\\\\Mg^(2+)O^(2-) \rightarrow MgO\\\\Cr^(4+)I^-\rightarrow CrI_4\\\\Cr^(4+)O^(2-)\rightarrow CrO_2`

Best regards!