Question

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

Answer 1

Answer: A) The balls are made of the same material.

Step-by-step explanation: Specific heat = (Heat transferred) ÷ (mass × temperature difference).

Specific heat of first ball = (2.5) ÷ (100 × temperature difference)

Specific heat of second ball = (5.0) ÷ (200 × temperature difference)

Dividing the second equation by the first

Specific heat of first ball = Specific heat of second ball

So both balls are made of the same material as they have the same specific heat.

Answer 2

Hey this is what i found on the internet

specific heat (Cp) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)

the equation related to this theory is
Q=m Cp ΔT

Where Q is the energy gained or lost from the system
m is the mass of the object
Cp is the specific heat of the material
ΔT is the change in temperature