Question

How do I solve this?

Answer 1

`\bf 4sin(\theta)+1=3\implies 4sin(\theta)=2\implies sin(\theta)=\cfrac{2}{4} \\\\\\ sin(\theta)=\cfrac{1}{2}\implies sin^(-1)[sin(\theta)]=sin^(-1)\left( \cfrac{1}{2} \right)\implies \theta=sin^(-1)\left( \cfrac{1}{2} \right)`