Question

Write a slope-intercept equation for a line passing through the given point that is parallel to the given line. Then write a second equation for a line passing through the given point that is perpendicular to the given line.(-5,0), y= -0.3x + 4.9

Answer 1

Given

Point

(-5, 0)

Slope

-0.3

Procedure

a) Parallel

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

m = -0.3

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-5,0). When x of the line is -5, y of the line must be 0.

`\begin{gathered} b=y-mx \\ b=0-(-0.3)\cdot(-5) \\ b=-1.5 \end{gathered}`

The equation of the line that passes through the point (-5,0) with a slope of -0.3

`y=-0.3x-1.5`

b) perpendicular

For perpendicular line m = 0.3

Now, what about b, the y-intercept?

`\begin{gathered} b=y-mx \\ b=0-0.3\cdot(-5) \\ b=+1.5 \end{gathered}`

The equation of the line that passes through the point (-5,0) with a slope of 0.3

`y=0.3x+1.5`