Question

PLEASE help?!

A bag holds 3 blue marbles, 5 red marbles, and 2 green marbles. Find the probability of choosing a red marble and then a green marble with replacement.
A. 1/10
B. 1/2
C. 1/9
D. 1/5

Answer 1

I think it is B. But I am not sure.

Answer 2

The calculated probability of choosing a red marble and then a green marble with replacement is A. 1/10

How to determine the probability of choosing a red marble and then a green marble

From the question, we have the following parameters that can be used in our computation:

3 blue marbles, 5 red marbles, and 2 green marbles

So, we have

Total = 3 + 5 + 2

Total = 10

Using the above as a guide, we have the following:

P(Red) = Red/Total and

P(Green) = Green/Total

Substitute the known values into the equation

P(Red) = 5/10 = 1/2

P(Green) = 2/10 = 1/5

So, we have

P(Red and Green) = 1/2 * 1/5

Evaluate

P(Red and Green) = 1/10

Hence, the probability of choosing a red marble and then a green marble is 1/10