Question

What is the mass of 0.12 mol of Mg(NO3)2?

Answer 1

I know the answer is 148.3148 g/mol.

Answer 2

`17.796\frac{\text{g}}{\text{mol}}`

Explanation:

We are asked to find the mass of 0.12 mole of Magnesium Nitrate
`\text{Mg(NO3)}2`.

We know that molar mass of Magnesium Nitrate is
`183.4\frac{\text{g}}{\text{mol}}`.

To find mass of 0.12 mol of Magnesium Nitrate, we will multiply
`183.4\frac{\text{g}}{\text{mol}}` by 0.12

`0.12* 183.4\frac{\text{g}}{\text{mol}}`

`17.796\frac{\text{g}}{\text{mol}}`

Therefore, the mass of 0.12 mol of Magnesium Nitrate is
`17.796\frac{\text{g}}{\text{mol}}`.