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Given the line 6x-4y=12 find the equation of a parallel line that passes through the point (3,5)

User RaduM
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First, we need to find the slope of the line they gave us. To do this we need to put the equation in slope intercept form , where m=slope, and (0,b)=y-intercept.the slope of this line is -5/4. We need a line perpendicular to this line so our slope needs to be 4/5. (Flip the slope and change the sign.) Now we use the point slope formula , where m=slope and (x1,y1)=the given point. Our m=4/5 and our point is (x1,y1)=(3,2)<--slope intercept form of a line

User StackHeapCollision
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