Answer: X'(0,6) Y'(10,4) Z'(-3,-1)
Explanation:
Given: Triangle XYZ is reflected across the y-axis.
The coordinates of the vertices of triangle XYZ are
X(0,−6) Y(−10,4) Z(3,−1)
We know that the rule for a reflection over the y -axis is
.
Then, the coordinates of X'Y'Z' will be


