Question

YZ has endpoint Y(-1,-11) and Z(-1-3) Find the length of YZ to the nearest tenth

Answer 1

≡ We know that:
⇔
`Y(-1,-11)`
⇔
`Z(-1,-3)`

≡ Solution:
⇒
`YZ= \sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}}`
⇒
`YZ=\sqrt{(-1-(-1))^(2)+(-3-(-11))^(2)}}`
⇒
`YZ=\sqrt{(0)^(2)+(8)^(2)}}`
⇒
`YZ=√(64)=\boxed{8}`

Answer 2

Answer 8

Distance formula sq rt of. (-3--11)^2+(-1--1)^2.( -3+11) = (8)^2 +0
Sq rt of 64 is 8