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If f'(x)=2/x and f(sqrt(e))=5, then f(e)=

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f'(x)=\frac2x

\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C


f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C

\implies 5=\frac22\ln e+C

\implies C=4

\implies f(x)=2\ln|x|+4

\implies f(e)=2\ln|e|+4=6
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