Question

Find the vertex for the parabola whose equation is given by writing the equation in the form y = ax² +bx+c.y=(x-4)²-15(Type an ordered pair.)The vertex is

Answer 1

Given:

`y=\left(x-4\right)^2-15=x^2-8x+1`

Required:

To find the vertex.

Answer:

The vertex is given by,

`\begin{gathered} V=((-b)/(2a),(b^2-4ac)/(4a)) \\ V=((8)/(2),(64-4)/(4)) \\ V=(4,(60)/(4)) \\ V=(4,15) \end{gathered}`

Final Answer:

The oredered pair of vertex(V) is,

`V=(4,15)`