Question

Can someone please please help me on this algebra problem I’m stuck on answering the question?

Answer 1

Step-by-step explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

`\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =(3+(-1))/(2) \\ =(3-1)/(2) \\ =(2)/(2) \\ =1 \end{gathered}`

Answer: Midline=1

1) Amplitude

`\text{Amplitude =}2`

2) Periods

`\begin{gathered} \text{Period}=6 \\ \Rightarrow b=(2\pi)/(6) \end{gathered}`

4) The trigonometric equation is,

`\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos ((2\pi)/(6)x)+1 \end{gathered}`

Answer:

`y=2\cos ((2\pi)/(6)x)+1`