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From $2003$ onward, the number of daily visitors to a website increased by $200\%$ every two years. So, for example, the number of visitors in $2011$ was $200\%$ more than the number of visitors in $2009$. In what year was the number of daily visitors $800\%$ more than the number of daily visitors in $2003$?

User Harrybvp
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2 Answers

2 votes

Final answer:

The number of daily visitors to the website was 800% more than in 2003 in the year 2007, based on the pattern of increasing by 200% every two years.

Step-by-step explanation:

We need to calculate when the number of daily visitors to a website was 800\% more than in 2003, given that the visitors increased by 200\% every two years. An increase of 800\% implies the number is 9 times (since 100\% + 800\% = 900\% or 9 times) the original count. Since the visitors increase by 200\% (which means tripling the number) every two years, we can write the equation:3^n = 9, where n is the number of 2-year periods after 2003.

To solve 3^n = 9, we find that 3^2 = 9, so n = 2. Each n represents 2 years, so 2 * 2 years = 4 years after 2003. Hence, the number of visitors was 800\% more than in 2003 in the year 2003 + 4 = 2007.

User Jonathan Mitchell
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5 votes

Answer:

2007

Step-by-step explanation:

User Kaushal Trivedi
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