Question

How do I solve negative 2 ninths minus negative 1

Answer 1

`-(2)/(9)-(-1)`

this can be rewritten like so

`-(2)/(9)+1`

start by remembering how to substract or add fractions.

`(a)/(b)\pm(b)/(c)=(ac\pm bd)/(bc)`

now apply the formula on your fraction

`\begin{gathered} -(2)/(9)+(1)/(1)=((-2\cdot1)+(9\cdot1))/((9\cdot1)) \\ -(2)/(9)+(1)/(1)=(-2+9)/(9) \\ -(2)/(9)+(1)/(1)=(7)/(9) \end{gathered}`