62.1k views
3 votes
An amount of $700 is invested partly at 8% and partly at 10%. The yearly income from both investments is $64. The amount invested at 8% is k dollars. What is the value of k?

User Ser
by
7.8k points

1 Answer

1 vote
A8% is X
10% is 700-X

X(.08)+ .10(700-X)= 64
.08x+ 70-.10X=64
-.02X+70=64
-70=-70
-.02x= -6
Divide by -.02
X= 300

Answer $300 was invested at 8%

Check 300 times .08= 24. 700-300=400 times .10 = 40 and 24+40=64
User JonAlb
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories