Question

Henry has a fair number pyramid with four faces and a spinner with three equal sized colored sections. what is the probability that the number pyramid will land on three and the spinner will stop on blue?

Answer 1

P(pyramid landing on 3) = 1/4
P(spinner stopping on blue) = 1/3

P(both) = 1/4 * 1/3 = 1/12 <===

Answer 2

Answer:
`(1)/(12)`

Explanation:

Given : The number of faces in a fair number pyramid (1,2,3,4) =4

Let A be the event that number pyramid will land on three.

Then,
`P(A)=(1)/(4)`

The number of equal sized colored sections in spinners= 3

Let B be the event that the spinner will stop on blue.

Then,
`P(B)=(1)/(3)`

Since, both the events A and B are independent.

Thus, the probability that the number pyramid will land on three and the spinner will stop on blue is given by :-

`P(A\cap B)=P(A)* P(B)\\\\=(1)/(4)*(1)/(3)=(1)/(12)`

Hence, the probability that the number pyramid will land on three and the spinner will stop on blue =
`(1)/(12)`