Question

A scientist recorded the movement of a pendulum for 10 s. The scientist began recording when the pendulum was at its resting position. The pendulum then moved right (positive displacement) and left (negative displacement) several times. The pendulum took 4 s to swing to the right and the left and then return to its resting position. The pendulum’s furthest distance to either side was 6 in. Graph the function that represents the pendulum’s displacement as a function of time.

Answer 1

The pendulum begins being planned at harmony position, this recommends you utilize a sine work since sin(0)=0
The time it takes to make one full upheaval is what's known as the period, spoken to by a T. You are given T= 4 sec. The separation from harmony is the plentifulness, An of the capacity which is given to be 6 in.
General wave work:
f(t) = A*sin( t*2pi/T - b) + c
A = |amplitude| ; remove from the midpoint
T = period; time it takes to make one full unrest
b = shifts the diagram right/left
c = shifts the diagram up/down
This diagram lies appropriately on the hub so there will be no compelling reason to move the chart
f(t) = 6*sin(t*pi/2)
y-pivot will be units of inches and x-hub, seconds