Question

In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.

A. 30.2 degrees

B. 35.3 degrees

C. 59.8 degrees

D. 54.7 degrees

Answer 1

Using the Law of Sines
a / sine A = c / sine C
9 / 0.70711 = 11 / sine C
sine C = 11 * 0.70711 / 9
sine C = 0.8642455556
Angle C = arc sine ( 0.8642455556 )
arc sine ( 0.8642455556 ) = 59.796

answer is C

Answer 2

I think it is B......