Question

The question is to solve: 72 = logx

Answer 1

`\bf 72=log(x)\iff 72=log_(10)(x)\\\\ -----------------------------\\\\ \textit{cancellation rules}\\\\ log_{{ a}}{{ a}}^x\implies x\qquad \qquad {{ a}}^{log_{{ a}}x}=x\impliedby \textit{let's use this one}\\\\ -----------------------------\\\\ 10^(72)=10^{log_(10)(x)}\implies 10^(72)=x`

Answer 2

Answer:
`x = 10^(72)`
Explanation: Logarithms are usually written in base of 10, unless otherwise specified.

So, we can rewrite the logarithm as:

`72 = log_(10) x`

Rewriting it in exponent form, we get:

`x = 10^(72)`