Answer:
Step-by-step explanation:
From the information given:
The population size N = 5
The sample size n = 2
∴
without replacement; the number of possible samples;
![^NC_n](https://img.qammunity.org/2022/formulas/business/college/8e6rbozwnz53983q1ia693dqws2opw41b1.png)
=
![^5C_2](https://img.qammunity.org/2022/formulas/mathematics/college/54cfmhrl2nnii2w43od9go7grjhb1zb9f4.png)
![= (5!)/(2!(5-2)!)](https://img.qammunity.org/2022/formulas/business/college/ortivb9lvpu9bg6b8bh7s50xne4qzb8f6j.png)
![= (5!)/(2!(3)!)](https://img.qammunity.org/2022/formulas/business/college/l6ax7edrmto91xep8h25djv0ojlwhdk1xi.png)
= 10
Thus, 10 different samples of 2 technicians each are possible.
DIfferent samples
S/No possible samples Mean
1 2 1 3/2 = 1.5
2 2 3 5/2 = 2.5
3 2 5 7/2 = 3.5
4 2 4 6/2 = 3
5 1 3 4/2 = 2
6 1 5 6/2 = 3
7 1 4 5/2 = 2.5
8 3 5 8/2 = 4
9 3 4 7/2 = 3.5
10 5 4 9/2 = 4.5
Total 30
Sample distribution for the sample mean
![= \frac {30} {10}](https://img.qammunity.org/2022/formulas/business/college/xmod3yua4xzdt2as1jako24if9hmg8s2xh.png)
= 3
Population mean =
![(2+1+3+5+4)/(5)](https://img.qammunity.org/2022/formulas/business/college/8a193ueirql47zs3c6h66x3nk0w2ngqak4.png)
![=(15 )/(5)](https://img.qammunity.org/2022/formulas/business/college/ewsge5tkbgv6q23eqclzyjstnbfq7hjlkp.png)
= 3
Thus, it is obvious that both means are equal