Answer:
59%
Explanation:
Mean =

Standard deviation =

We are supposed to find 0 what is the probability that a randomly selected student has a test score between 350 and 550
Formula :

at x = 350


at x = 550


So, P(-1.36<z<0.454)
P(z<0.45)-P(z<-1.36)
Using z score table
= 0.6736-0.0869
= 0.5867
= 58.6% ≈ 59%
Thus the probability that a randomly selected student has a test score between 350 and 550 is 59%