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34 votes
34 votes
need help with this question i already ready figured out that the rref is.
1 \: 0 \: - 4 \: - 3 \\ 0 \: \: 1 \: - 3 \: - 7\\ 0 \: \: 0 \: 0 \: 0

need help with this question i already ready figured out that the rref is. 1 \: 0 \: - 4 \: - 3 \\ 0 \: \: 1 \: - 3 \: - 7\\ 0 \: \: 0 \: 0 \: 0-example-1
User Grace
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1 Answer

18 votes
18 votes

Step-by-step explanation:


\begin{gathered} Given\text{ that the reduced row echelon form is the following:} \\ \begin{bmatrix}{1} & {0} & -{4} & |{-3} \\ {0} & {1} & -{3} & |-{7} \\ {0} & {0} & {0} & |{0} \\ & & & \end{bmatrix} \end{gathered}

Seeing as the last row is all zeroes, we can conclude that the system has many solutions.

The z column is not cleared out so x and y will be defined in terms of z. Therefore, z will be a parameter, i.e any real number.

Correct answer: B

x = -3 +4z

y = -7 + 3z

User KOUSIK MANDAL
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