Question

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below. Kaitlyn got a score of 79.7 this version has a mean of 73.7 and a standard deviation of 12.Pierce got a score of 237.2 this version has a mean of 227 and a standard deviation of 17.Norma got a score of 8.7 this version has a mean of 6.7 and a standard deviation of 0.8If the company has only one position to fill and prefers to fill it with the applicant who performed Best on the aptitude test which of the applicant should be offered the job

Answer 1

To compare each candidate score, we can convert each individual score to a z-score and compare them. The z-score is given by:

`z=(x-\mu)/(\sigma)`

where x represents the actual score, mu represents the mean and sigma represents the standard deviation.

Calculating the z-score of each candidate, we haev:

`\begin{gathered} z_(Kaitlyn)=(79.7-73.7)/(12)=0.5 \\ z_(Pierce)=(237.2-227)/(17)=0.6 \\ z_(Norma)=(8.7-6.7)/(0.8)=2.5 \end{gathered}`

The highest z-score is associated with the best performance.

The job should be given to Norma.