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What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?

User Huralnyk
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1 Answer

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The product of perpendicular line's slope (P) and the original line (I'm going to call it M) will always equal to minus one

=> -1= M(P)

With the equation
3y=-4x+2
->The slope is -4/3
M= -4/3

-1=M(P)
P= -1/M
=
(-1)/( (-3)/(4) )
= 4/3

The perpendicular slope is 3/4

For future reference (maybe?)
----> the perpendicular slope is the negative reciprocal of the original line's slope
User Dhamibirendra
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