Question

Four wires running through the corners of a square with sides of length 9.581 cm carry equal currents, 4.403 A. Calculate the magnetic field at the center of the square.

Answer 1

Given:

The length of the side is l = 9.581 cm

The current is I = 4.403 A

To find the magnetic field at the center of the square.

Step-by-step explanation:

The magnetic field at the center of the square can be calculated by the formula

`B\text{ = }(2√(2)\mu_0I)/(\pi l)`

Here, the constant is

`\mu_0=\text{ 4}\pi*10^(-7)\text{ H/m}`

On substituting the values, the magnetic field will be

`\begin{gathered} B=\frac{2√(2)*4\pi*10^(-7)\text{ }*4.403}{\pi*9.581*10^(-2)} \\ =\text{ 5.199 }*10^(-5)\text{ T} \\ =51.99\text{ }*10^(-6)\text{ T} \\ =51.99\text{ }\mu T \end{gathered}`