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Hi. I need help with these questions (see image)
Please show workings.


Hi. I need help with these questions (see image) Please show workings. ​-example-1

1 Answer

11 votes

Answer:

A:
(1)/(2√(x-1) )

B:
\frac{1}{4\sqrt[4]{x^(3) } }

c: 2x

Explanation:

To find the derivative of x raised to the nth power we use the following template


x^(n)=nx^(n-1)

Something else to keep in mind is that


\sqrt[n]{x^(y)}=x^(y/n)

So knowing this we can rewrite a as follows


√(x-1) =(x-1)^(1/2)

so we can use the template above and get


(1)/(2)(x-1)^(.5-1)

So that simplifies to


(1)/(2)*(x-1)^{-(1)/(2)


((x-1)^(-.5))/(2)


(1)/(2√(x-1) )

B: Same kind of deal here


\sqrt[4]{x}=x^{(1)/(4) }


(1)/(4) *x^{(1)/(4)-1}


\frac{x^{-(3)/(4)}}{4} =\frac{1}{4\sqrt[4]{x^(3) } }

C: this one is by far the easiest because the derivative of a constant is 0 so we can just apply the same template from before and get

2x

User Stanley Gong
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