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Sam is making a pennant in the shape of a triangle for his senior class photo. He wants the base length of this triangle to be 8 inches. The area of the pennant must be at most 20 square inches. (Sam doesn't want to buy more materials.) Write an inequality that describes the possible heights (in Inches) of the triangle. Use h for the height of the triangular pennant.

User Karesh A
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20 votes
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Sam is making a pennant in the shape of a triangle for his senior class photo. He wants the base length of this triangle to be 8 inches. The area of the pennant must be at most 20 square inches. (Sam doesn't want to buy more materials.) Write an inequality that describes the possible heights (in Inches) of the triangle. Use h for the height of the triangular pennant.​

we know that

The area of triangle is equal to


A=(1)/(2)\cdot b\cdot h

we have in this problem

b=8 in

at most -----> is less than or equal to

so


A\leq20\text{ in2}

substitute


\begin{gathered} (1)/(2)\cdot(8)\cdot h\leq20 \\ \text{solve for h} \\ 4\cdot h\leq20 \\ h\leq5\text{ in} \end{gathered}

therefore

the height must be less than or equal to 5 inches

User James Strachan
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