Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,128.76 kJ/mol ΔGf,CaO = −604.17 kJ/mol ΔGf,CO2 = −…

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asked Jul 10, 2018 4.2k views

2 Answers

Ben Bederson · Answer 1 · 2018-07-17T06:13:33+0000

Answer:
$\Delta G_(rxn)$ for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the
$\Delta G_(rxn)$ , we use the formula:

$\Delta G_(rxn)=\Delta G_(products)-\Delta G_(reactants)$

For the given chemical reaction:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

We are given:

$\Delta G_(CaCO_3)=-1128.76kJ/mol\\\Delta G_(CaO)=-604.17kJ/mol\\\Delta G_(CO_2)=-394.4kJ/mol$

Now, to calculate
$\Delta G_(rxn)$ , we put the values in the above equation:

$\Delta G_(rxn)=(\Delta G_(CaO)+\Delta G_(CO_2))-\Delta G_(CaCO_3)$

$\Delta G_(reaction)=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_(reaction)=130.19kJ/mol$

As, the value of
$\Delta G_(reaction)$ comes out to be positive, the reaction is said to be non-spontaneous reaction.