Question

How many moles of argon atoms are present in 17.2 L of argon gas at STP?

Answer 1

The mole of argon atoms that is present in 17.2L of argon is 0.7679 mole

Explanation:

Given parameters

• The volume of argon at STP = 17.2L

,

• Let x represents the mole of argon at STP

Recall that, 1 mole of a gas is equivalent to 22.4L at STP

The next thing is to establish a proportion between the number of moles and volume of the given gas

`\begin{gathered} 1\text{mole }\rightarrow\text{ 22.4L} \\ x\text{ mole }\rightarrow\text{ 17.2L} \\ \text{Cross multiply} \\ 1\cdot\text{ }17.2\text{ = x }\cdot\text{ 22.4} \\ 17.2\text{ = 22.4x} \\ \text{Divide both sides by 22.4} \\ (17.2)/(22.4)\text{ =}(22.4x)/(22.4) \\ x\text{ = 0.7679 mole} \end{gathered}`

Hence, the mole of argon atoms that is present in 17.2L of argon is 0.7679 mole