Question

A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. What is the horizontal velocity component of the ball? Round the answer to the nearest tenth of a m/s

Answer 1

Horizontal component of the speed is given as

`v_x = 25.4 m/s`

Step-by-step explanation:

As we know that if a vector is inclined at some angle with the horizontal then the component of the vector along and perpendicular to horizontal is given as

`A_x = Acos\theta`

`A_y = Asin\theta`

now here we need to find the component of velocity

so we know that

`v = 31 m/s`

`\theta = 35^0`

now we will have

`v_x = 31cos35`

`v_x = 25.4 m/s`

so horizontal component of the speed will be 25.4 m/s

Answer 2

The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle.
x-component of speed = (31 m/s)(cos 35°)
= 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s.