Question

If a photon has a frequency of 1.15 × 1015 hertz, what is the energy of the photon? Given: Planck's constant is 6.63 × 10-34 joule·seconds.

Answer 1

5.82 x 10-49 joules7.62 x 10-19 joules8.77 x 10-12 joules1.09 x 10-12 joules answer is b

Answer 2

Energy of photon,
`E=7.62* 10^(-19)\ J`

Step-by-step explanation:

It is given that,

The frequency of the photon,
`\\u=1.15* 10^(15)\ Hz`

Value of Planck's constant,
`h=6.63* 10^(-34)\ J-s`

We have to find the energy of the photon. The energy of photon is given by the product of Planck's constant and the frequency of photon. It is given by :

`E=h\\u`

`E=6.63* 10^(-34)\ J-s* 1.15* 10^(15)\ Hz`

`E=7.62* 10^(-19)\ J`

Hence, this the required solution for the energy of the photon.