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Pushing on the pump of a bottle of hand washing solution compresses a small spring which obeys Hooke's Law. If the potential energy of the spring is 0.0030 J when the spring is compressed 0.55 cm, determine the following.

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U = 1/2 * k * x²

U = 0.003J
x = 0.0055m
k spring constant
User Stephen Vernyi
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