Question

How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0°C to 80.0°C? (The specific heat of silver is 0.057 cal/g°C)

1.43 cal

0.0713 cal

5.70 cal

7.13 cal

Answer 1

1.43cal is the answer

Answer 2

Answer: The correct answer is 1.43 cal.

Step-by-step explanation:

The expression of heat in terms of mass and temperature is as follows;

`Q= mc\Delta T`

Here, Q is the heat, m is the mass of the object and
`\Delta T` is the change in temperature.

It is given in the problem that 1.25 grams of silver is cooled from 100.0°C to 80.0°C.

Calculate the change in temperature.

`\Delta T=100.0\°C- 80.0\°C`

`\Delta T= 20\°C`

Calculate the heat in calories.

`Q= mc\Delta T`

Put m= 1.25 grams,
`\Delta T= 20\°C` and c=0.057 cal/g°C.

`Q= (1.25)(0.057)(20)`

Q= 1.43 cal

Therefore, the amount of heat is 1.43 cal.