Question

Find the inverse of the logarithmic function y = log^2(x + 7)?

Answer 1

y=log^2(x+7) equals y=(7+x)*LogN^2 OR {{x=(-7.0*LogN^2.0+y)*LogN^(-2.0)}}

Answer 2

I'm assuming it's
`y = log_2(x + 7)`


`x = log_2(y + 7)`

`2^(x) = y + 7`

`y = 2^(x) - 7`

If it actually is
`y = log^2(x + 7)`,
the inverse is just
`y = e^(√(x)) - 7`