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Which expression is equivalent to 2x^2+2x-4/2x^2-4x+2

A) x+2/x-1
B) x+2
C) -2
D) x+2/x-2

User Kubilay
by
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2 Answers

5 votes
You need to factor the numerator and denominator...

(2x^2+4x-2x-4)/(2x^2-2x-2x+2)

(2x(x+2)-2(x+2))/(2x(x-1)-2(x-1))

((2x-2)(x+2))/((2x-2)(x-1)) so the (2x-2)s cancel out leaving

(x+2)/(x-1)
User Amun
by
8.2k points
5 votes

Answer:


(x+2)/(x-1)

Explanation:


((2x^2+2x-4))/((2x^2-4x+2))

Factor top and bottom separately


2x^2+2x-4


2x^2+4x-2x-4

Make two groups and take out GCf


2x(x+2)-2(x+2)

(x+2)(2x-2)

We factor the denominator


2x^2-4x+2


2x^2-2x-2x+2

Make two groups and take out GCf


2x(x-1)-2(x-1)

(x-1)(2x-2)


((2x^2+2x-4))/((2x^2-4x+2))=((x+2)(2x-2))/((x-1)(2x-2))

2x-2 cancel out

So answer is
(x+2)/(x-1)


User Max Uppenkamp
by
8.3k points

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