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Evaulate the definite integral (The s is the integration symbol with indicated values)

4
S ((t^6)-(t^2))/(t^4) dt
1

User Royhowie
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1 Answer

4 votes

\displaystyle\int\limits_(t=1)^(t=4)(t^6-t^2)/(t^4)\,\mathrm dt=\int_1^4\left(t^2-\frac1{t^2}\right)\,\mathrm dt=\left(\frac13t^3+\frac1t\right)\bigg|_(t=1)^(t=4)

which evaluates to
(259)/(12)-\frac43=\frac{81}4.
User NeeruKSingh
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