Question

Ten percent of cereal boxes have a prize. A student wants to estimate the probability that when 8 boxes are purchased, fewer than 3 have a prize.

To do this, the student uses a random number table to pick 8 numbers from 0 to 9. She lets 0 represent a box with a prize and 1 through 9 represent a box without a prize. She repeats this for a total of 12 trials. The results are shown in the table.

65720797 56708801 96902111 61803079 80659604 01609960
35904439 31413140 16206837 49947066 65431196 99141179
Select from the drop-down menus to correctly complete each statement.
To estimate the probability that fewer than 3 out of 8 boxes have a prize, the student must count the number of trials with and divide by the number of trials.

This gives an estimated probability of about .

Answer 1

fewer than 3 0s and the second part is 0.92

Answer 2

Answer with explanation:

The student uses a random number table to pick 8 numbers from 0 to 9.

She lets 0 represent a box with a prize and 1 through 9 represent a box without a prize. She repeats this for a total of 12 trials.

The results are shown in the table as:

65720797 56708801 96902111 61803079 80659604 01609960 35904439 31413140 16206837 49947066 65431196 99141179

To estimate the probability that fewer than 3 out of 8 boxes have a prize, the student must count the number of trials with fewer than three 0's. and divide by the number of trials.

The outcomes that have less than 3 0's ( i.e. it must have either no zero, 1 zero or 2 zero) are:

65720797 56708801 96902111 61803079 80659604 35904439 31413140 16206837 49947066 65431196 99141179.

So, number of outcomes with fewer than 3 0's are: 11

This gives an estimated probability of about : 0.92

( since,

`=(11)/(12)=0.916666666`

which is approximately equal to 0.92 )