Question

Another metal phosphate is aluminum phosphate. It will behave similar to calcium phosphate in an acid solution. What is the net ionic equation including phases for AlPO4(s) dissolving in H3O+(aq)?

Answer 1

The net ionic equation for dissolving aluminum phosphate (AlPO4) in hydronium ion (H3O+(aq)) acidic solution is AlPO4(s) + 3H3O+(aq) → Al3+(aq) + H2PO4-(aq) + 3H2O(l). It represents the dissolution of the insoluble compound in acid, with aluminum becoming soluble.

Step-by-step explanation:

The question asks for the net ionic equation for the dissolution of aluminum phosphate (AlPO4), an insoluble salt, in acidic solution with H3O+(aq). Given that aluminum phosphate is insoluble, we assume it will react with the hydronium ions to form soluble products. Since aluminum is amphoteric, it can react with acids to dissolve. Here's the balanced net ionic equation:

1. 
   
3. Write out the full reaction of AlPO4(s) with H3O+(aq): AlPO4(s) + 3H3O+(aq) → Al3+(aq) + H2PO4-(aq) + 3H2O(l)
4. 
   
6. Identify and cancel out the spectator ions if present. In this case, all products are either precipitate or involved in the reaction, hence no spectator ions to cancel.
7. 
   
9. Write the net ionic equation: AlPO4(s) + 3H3O+(aq) → Al3+(aq) + H2PO4-(aq) + 3H2O(l)

This reaction shows the dissolution of an insoluble phosphate in the presence of hydronium ions.

Answer 2

`AlPO_4(s) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^(-2)(aq) +Al^(+3)(aq)`

Step-by-step explanation:

Hi, the aluminum phosphate will dissociate when mixed in water:

`AlPO_4 (s) \longrightarrow Al^(+3) (aq) + PO_4^(-3)(aq)`

or if you prefer:

`AlPO_4 (s) + 3 H_2O (l) \longrightarrow Al(OH)_3(aq) + H_3PO_4(aq)`

Given that the solution is acid, the phosphate (
`PO_4^(-3)`) will react with the
`H_3O^+` because of the phosphate's basic power:

`PO_4^(-3)(aq) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^(-2)(aq)`

The net ionic equation:

`AlPO_4(s) + H_3O^+(aq) \longrightarrow H_2O(l) + HPO_4^(-2)(aq) +Al^(+3)(aq)`