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Jake drags a sled of mass 18 kg across the snow. The sled is attached to a rope that he pulls with a force of 70 N at an angle of 40°. If there is no friction, what is the normal force acting on the sled?

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Answer: The normal force acting on the sled 131.4048 Newtons.

Step-by-step explanation:

On breaking up force of 70 N into vertical and horizontal components:

Vertical components:
f\cos\theta

Horizontal components:
f\sin\theta

The normal force is force acting perpendicular on an object.It is a balanced force.


mg=N+f\sin\theta


N=mg-f\sin\theta=18 kg* 9.8 m/s^2-70 N* 0.6427=131.4048 N

The normal force acting on the sled 131.4048 Newtons.

Jake drags a sled of mass 18 kg across the snow. The sled is attached to a rope that-example-1
User Kirill Strizhak
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