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Chord AC intersects chord BD at point P in circle Z.

AP=4 cm
BP=5 cm
PC=8 cm



What is PD?

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Chord AC intersects chord BD at point P in circle Z. AP=4 cm BP=5 cm PC=8 cm What-example-1

2 Answers

5 votes
Using the chord intersection theorem, AP · PC = BP · PD
Thus, 4 · 8 = 5 · PD
32 = 5PD
PD = 6.4 cm
User Ryan Bennetts
by
6.5k points
7 votes

Answer: 6.4 cm

Explanation:

By the internal intersection of chords theorem,

When two chords intersect each other inside a circle, the products of their segments are equal.

In the given diagram, the chords AC and BD are intersecting internally at point P,

Thus, We can write,


BP* PD = AP* PC


\implies 5* PD = 4* 8


\implies 5PD=32


\implies PD = 6.4

Hence, the measurement of segment PD = 6.4 cm.

User Saastn
by
5.6k points