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A rectangle has a perimeter of 48 feet and a length of 14 feet. Which equation can you solve to find the width?

a. 2n+28=48
b. 48-n=28
c. 14+n=48
d. 2n+14=48

User Mhenning
by
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2 Answers

2 votes
48 = 14*2 + 2n
2n + 28 = 48
Ans. A
User Parker Selbert
by
8.5k points
6 votes

Answer: The equation is A .

Explanation:

Given :

A rectangle has a perimeter of 48 feet and a length of 14 feet.

To find : Which equation can you solve to find the width?

Formula used : Perimeter of rectangle = 2 ( length + width ).

Solution : We have perimeter = 48 feet.

Length = 14 feet.

Let the width of the rectangle = n .

Plugging the values of length and width in above formula.

48 = 2 ( 14 + n ).

48 = 28 + 2 n .

2n+28=48.

Therefore, The equation is A .

User Psx
by
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