Question

A soccer ball is kicked at an angle of 30° to the horizontal with an initial velocity of 16 m/s. How high does the soccer ball go?

A. 9.8 m
B. 3.3 m
C. 0.6 m
D. 0.2 m

Answer 1

Vertical component of velocity = 16sin(30°) = 8m/s

at the highest point of flight, the velocity of the ball is 0 (that moment when it stops before starting to fall) so:

`v^2=u^2+2as`

`0^2=8^2+(2*-9.81* s)`

`s= (0^2-8^2)/(2*-9.81)`
s=3.26m

So rounding up gives option B. (3.3m)