Question

Which of the following is the change in energy of an atom emitting a photon of wavelength of 4.35 meters? [Planck's constant, h = 6.626 × 10-34 Js, c = 2.998 × 108 meters/second] a)1.986 × 10-25 joules b) 2.823 × 10-34 joules c)9.614 × 10-42 joules d)4.567 × 10-26 joules

Answer 1

I really think it is d

Answer 2

d)
`4.567 * 10^(-26)` joules

Step-by-step explanation:

• Energy of the photon having wavelength is given as:

• 
  `E = (h*c)/(wavelength)`
• h = 6.626 × 10-34 , c = 2.998 × 108 meters/second , wavelength = 4.35

`E = ((6.626*10^(-34))(2.998*10^(8)))/(4.35)` =
`4.567 * 10^(-26)` Joules