Question

Peter buys a bag of 21 sweets. In the bag there 13 red sweets, 6 green sweets and 2 yellow sweets Peter likes red sweets and eats 3 of them He then asks his sister to choose one sweet at random from the bag. There are 2 questions to answer. What is the probability that she chooses a red sweet? what is the probability that she chooses an orange sweet?

Answer 1

you have to write this as a fraction look at the total number of sweets and turn it in to a fraction there are 21 sweets so that's the denominator there are 13 red sweets so that's the numerator but he took away three so 10/21 is the probability of picking a red sweet

Answer 2

probability=number of specific outcomes/total number of outcomes...

Since Peter eats 3 reds there are only 10 reds and 18 total sweets left, therefore the probability of his sister picking a red randomly is:

10/18=5/9

There are no orange sweets so the probability of picking one is zero.