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how many times more massive is mr.ford than a Neautron ? if the mass of a neutron is 0.000000000000000000000000000167493 kg and the mass of mr. ford is 77.56 kg Perform your work in scientific notation, concluding in a sentence.

User Jay Fridge
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1 Answer

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Write the mass of the Neutron in scientific notation. Moving the decimal point 27 places to the right:

0.00000000000000000000000000167493 = 1.67493 x 10^-27

Divide the mass of Mr. Ford over the mass of a Neutron to find how many times more massive he is:


\begin{gathered} \frac{77.56\operatorname{kg}}{1.67493\cdot10^(-27)\operatorname{kg}}^{}=(77.56)/(1.67493)\cdot10^(27) \\ =46.3064\ldots\cdot10^(27) \\ \approx4.631\cdot10^(28) \end{gathered}

Therefore, Mr. Ford is 4.631x10^28 times more massive than a neutron.

User Konrad Lindenbach
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