Question

Factor 6y2 + 13y + 15.

A) (2y + 1)(3y + 5)
B) (3y + 1)(2y + 5)
C) (2y + 1)(4y + 5)
D) (2y + 5)(3y + 5)

Answer 1

`6y^2 + 13y + 15 : \text{Factor}`

In general, given
`a{x}^(2)+bx+c` the factored form is:


`a(x- (-b+ √(b^2-4ac) )/(2a))(x-(-b- √(b^2-4ac))/(2a)`

In this case, a=6, b=13 and c=15.


`6(y- (-13+ √(13^2-4*6*15))/(2*6))(y- (-13- √(13^2-4*6*15))/(2*6))`


`6(y- (-13+ √(191i) )/(12)(y-(-13- √(191i) )/(12)`